Pulling the receipt…
Pulling the receipt…
MEBRO
06/09/26 · 12:12 PM UTC · 17 SOURCES
EXHIBIT A
What you submitted
“An odds of 1 in 10^1,822 for an election result is equivalent to correctly calling about 6,053 fair coin flips in a row.”
TL;DR ·Statistical conversion confirms the probability of 6,053 consecutive fair coin flips equals approximately 1 in 10^1,822.
The mathematical probability of a fair coin landing on a specific side is exactly 0.5 or 1/2 . When calculating the likelihood of multiple independent events occurring in a sequence, such as consecutive coin flips, the probabilities are multiplied . To find the number of flips equivalent to a 1 in 10^1,822 chance, the equation is (1/2)^n = 1/10^1,822. Using logarithmic conversion, n = 1,822 / log10(2), which results in approximately 6,052.55 . Therefore, calling 6,053 fair coin flips in a row is the correct mathematical equivalent for the stated odds . While some research indicates that physical coin tosses may have a slight same side bias of approximately 1%, the standard statistical model for a fair coin remains a 50/50 probability . The mention of election results in this context often refers to statistical models used in econometrics and presidential voting analysis .
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